Mark M. answered 10/20/19
Retired math prof. Very extensive Precalculus tutoring experience.
x2 + 4x + 4 ≥ 9
x2 + 4x - 5 ≥ 0
(x + 5)(x - 1) ≥ 0
(x + 5)(x - 1) = 0 when x = 1 or -5
When x < -5, (x + 5)(x - 1) > 0
When -5 < x < 1, (x + 5)(x - 1) < 0
When x > 1, (x + 5)(x - 1) > 0
Solution set: (-∞, -5] ∪ [1, ∞)
-------------------------------------------
2x3 + 13x2 - 8x - 52 ≥ 0
x2(2x + 13) - 4(2x + 13) ≥ 0
(2x + 13)(x2 - 4) ≥ 0
(2x + 13)(x - 2)(x + 2) ≥ 0
(2x + 13)(x - 2)(x + 2) = 0 when x = -13/2, 2, and -2.
Check the sign of (2x + 13)(x - 2)(x + 2) to the left of -13/2, between -13/2 and -2, between -2 and 2, and to the right of 2.