How to solve Calculations for macronutrients?

Question

(include the mineral base but do not include the Wolfe's Trace Element or Vitamin Solution)

Xylose Flask

1. Moles of carbon per liter
2. moles of nitrogen per liter
3. moles of sulfur per litler
4. moles of phosphorus per liter

Glucose Flask

1. moles of carbon per liter
2. moles of nitrogen per liter
3. moles of sulfur per liter
4. moles of phosphorous per liter

Answer 1

1. NaCl : Molar mass: 22.99+35.45= 58.44g/mol

Moles of NaCl: 1g/ 58.44 g/mol= 0.0171mol

So, Na= 0.0171 mol

Chlorine: 0.0171 mol

1. MgCl2 *6H2O (0.4g)

Molar mass: 24.31+ (2x 35.45) + (6x 18.02)= 203.69 g/mol

moles of MgCl2 *6H2O= 0.4g/ 203.60g/mol= 0.002mol

Therefore, Mg: 0.002 mol

Cl: 0.004 mol

1. CaCl2 *2H2O (0.1g)

molar mass: 40.08+ (2x35.45) + (2x 18.02)= 147.02g/mol

Moles of CaCl2 * 2H2O: 0.1g/ 147.02g/mol= 0.00068 mol

So, Ca: 0.00068mol

Cl: 0.00136 mol

1. KH₂PO₄ (0.2 g):
2. Molar mass: 39.1+(2×1.008)+30.97+(4×15.999)=136.09 

Moles of KH₂PO₄: 0.2 g136.09 g/mol=0.00147 

Potassium: 0.00147 mol (not a target element)

Phosphorus: 0.00147 mol

Oxygen: Not a target element

1. KCl (0.5g)

molar mass: 39.1+35.45=74.55g/mol

moles of KCl: 74.55g/mol0.5g​=0.0067mol

So, otassium: 0.0067 mol

Chlorine: 0.0067 mol

1. NH4Cl (0.2g)

molar mass: 14.01+(4×1.008)+35.45=53.49g/mol

moles of Nh4Cl: 53.49g/mol0.2g​=0.0037mol

Therefore, Nitrogen: 0.0037 mol

1. MgSO4 (0.2g)

Molar mass: 24.31+32.07+(4×15.999)=120.37g/mol

moles of MgSO4: 120.37g/mol0.2g​=0.00166mol

Therefore, Sulfur: 0.00166mol