
Edward A. answered 09/24/19
High School Math Whiz grown up--I've even tutored my grandchildren
Selena, here’s a way to approach this:
the elements of a are either in b or not in b.
Similarly, the elements of b are either in a or not in a.
so Let ainb be the a elements that are also in b,
Let aalone be the a elements that are not in b
Let bina be the b elements that are also in a.
Let balone be the b elements that are not in a.
Now translate what we know into math.
First, notice that ainb = bina
24 = ainb + aalone
10 = bina + balone = ainb + balone
28 = aalone + balone + ainb
From the last two, subtract and find
18 = aalone
from that and the first line, we see that
6 = ainb
and that’s the answer to the question.
So, for the second question, do the same thing: put a name on each quantity, then translate the numbers you know into expressions. Then you can find
aalone + balone + ainb
If you have any questions, please ask.