
Mark M. answered 07/25/19
Mathematics Teacher - NCLB Highly Qualified
|| -2 + 2i || = 2√2
θ = 3π/4
(2√2)16 (cos 12π + i sin 12π)
(216)(28) (cos 0 + i sin 0)
224
Nijaansh P.
asked 07/25/19Answer is suppose to be: 2^24 Cis(0)
but I got some crazy: 16777216 cis (2160)
So, I'm messing up somewhere while trying to find theta. Since 2^24 is same as 16777216.
Mark M. answered 07/25/19
Mathematics Teacher - NCLB Highly Qualified
|| -2 + 2i || = 2√2
θ = 3π/4
(2√2)16 (cos 12π + i sin 12π)
(216)(28) (cos 0 + i sin 0)
224
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