Mark M. answered 07/12/19
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Retired Math prof with teaching and tutoring experience in trig.
sinx + cosx = √2[(1/√2)sinx + (1/√2)cosx)]
= √2[cos(π/4)sinx + sin(π/4)cosx] = √2sin(x + π/4) = √2sin[x + (1/4)π]
A = 1/4