
Mark M. answered 12/10/14
Tutor
5.0
(278)
Mathematics Teacher - NCLB Highly Qualified
Put the function into graphing form: f(x) = a(x - h)2 + k
f(x) = 3x2 - 6x - 24 Complete the square
f(x) = 3(x2 - 2x + 1) - 24 - 3
f(x) = 3(x - 1)2 - 27
Vertex = (1, -27)
x-intercepts are at f(x) = 0
0 = 3(x - 1)2 - 27
27 = 3(x - 1)2
9 = 3(x - 1)2
3 = (x - 1)2
±√3 = x - 1
1 ±√3 = x
x-intercepts are at 1 ±√3.
y-intercepts are at x = 0.
y = 3(0 - 1)2 - 27
y = - 3 - 27
y = - 30
The y-intercept is at -30.