If I understand what you are asking, it is impossible.
Original number is 10t + u and the digit reversed number is 10u + t
The sum of the original plus the reversed number is 11(t+u).
Since 65 is NOT divisible by 11, the procedure is not possilbe.
Genesis A.
asked 04/18/19If I understand what you are asking, it is impossible.
Original number is 10t + u and the digit reversed number is 10u + t
The sum of the original plus the reversed number is 11(t+u).
Since 65 is NOT divisible by 11, the procedure is not possilbe.
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