What volume in mL of 1.24 M strontium hydroxide would be needed to completely react with 55mL of 0.950 M cobalt (I) nitrate?

Question

1 Sr(OH)_2 + 2CoNo_2 = 1 Sr(No_2)_2 (aq) + 2CoOH (s)

Answer 1

1 Sr(OH)_2 + 2CoNo_2 = 1 Sr(No_2)_2 (aq) + 2CoOH (s)

First, you have written CoNO2. This is cobalt I nitrite. Cobalt I nitrate is CoNO3,

1 Sr(OH)2 + 2CoNO3 = 1 Sr(NO3)2 (aq) + 2CoOH (s) is the proper equation, balanced.

55mL CoNO3 x (1L/1000mL) x (0.950 mol CoNO3/1 L CoNO3) = .05225 mol CoNO3

.05225 mol CoNO3 x (1 mol Sr(OH)2/2 mol CoNO3) = .026125 mol Sr(OH)2

.026125 mol Sr(OH)2 x (1 L Sr(OH)2 /1.24 mol Sr(OH)2 ) x (1000mL/1L) = 21.1 mL Sr(OH)2