Yes.
(a/b) = (x/y) => ay = xb => y/b = x/a
Now add 1 to each side
(y-b)/b = (x-a)/a => (x-a)/(y-b) = a/b
Yes.
(a/b) = (x/y) => ay = xb => y/b = x/a
Now add 1 to each side
(y-b)/b = (x-a)/a => (x-a)/(y-b) = a/b
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