
Michael Z. answered 11/16/19
Mathematics Tutor
Before we do anything to solve this, let's draw a picture to help visualize the problem. Draw a circle and label the center M. Make a point anywhere outside the circle and label it E. Draw a line connecting points M and E. Draw a line from point E tangent to the circle and label that point of intersection as T. Lastly, draw a radius from M to point T. You should now have triangle ETM.
We know MT is 4, so write a 4 along MT. We're also given that ET is 1/3 the length of EM. Label EM with x and label ET with x/3
A line tangent to a circle is perpendicular to the radius at that tangent point. In triangle ETM, point T is a right angle. We can now use the Pythagorean Theorem to solve for x.
a2 + b2 = c2
42 + (x/3)2 = x2
16 + x2/9 = x2
144 + x2 = 9x2
144 = 8x2
18 = x2
x = ±√18
x = √18 We're dealing with lengths that cannot be negative, so we ignore the negative answer.
x = 3√2
EM = 3√2
ET = x/3 = (3√2)/3 = √2