6 cakes and 5 pies were sold
This looks like a job for a substitution with a system of two equations and two unknowns
Let x = cakes
Let y = pies
Equation 1 can represent total baked goods sold
x + y = 11
Equation 2 can represent total cost $145
15x + 11y = 145
Equation 1 is ideal for setting up a substitution
x + y = 11
AND
y = 11 - x
We will use this quantity for y in Equation 2
15x + 11y = 145
15x + 11(11 - x) = 145
15x + 121 - 11x = 145
Combine like terms
15x - 11x + 121 = 145
4x + 121 = 145
Subtract 121 from both sides of the equation
4x = 145 - 121
4x = 24
Divide both sides by 4
x = 6
We already know from Equation 1
y = 11 -x
y = 11 - 6
y = 5
We use our values in both equations to check
x + y = 11
6 + 5 = 11
15(6) + 11(5) = 145
90 + 55 + 145
145 = 145
Of course you can do this by elimination as another means of checking give it a try.
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