J.R. S. answered 10/17/18
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
You can use V1C1 = V2C2
(x L)(10.0 mg/L) = (0.016 L)(6.5 mg/L)
x = 0.0104 L = 10.4 ml
Hannah M.
asked 10/17/18J.R. S. answered 10/17/18
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
You can use V1C1 = V2C2
(x L)(10.0 mg/L) = (0.016 L)(6.5 mg/L)
x = 0.0104 L = 10.4 ml
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