Pre calculus question !!!

Question

How many solutions does the equation sin(x) sin(2x) sin(3x)... sin(11x) sin(12x) = 0 have in the interval (0,π ] ? 

 

(a) 11   (b) 12   (c) 24   (d) 46   (e) 68

Answer 1

This equation will have a root wherever the ordinate = an integer * π.

In order to get the answer you will have to count how many unique values there are, e.g. 6π/12 = 5π/10 = π/2 which can only be counted once.

 

Good luck!