Chemistry Problem

Question

1 FeS + 2 HCl → 1 FeCl2 + 1 H2S

 

Determine the mass (in g) of H2S that would be produced when 8.21×10-1 g of HCl reacts with an excess of FeS.

Answer 1

FeS + 2HCl ==> FeCl₂ + H₂S

moles HCl present = 0.821 g x 1 mole/36.5 g = 0.0225 moles 

 

moles H₂S produced = 0.0225 moles HCl x 1 mol H2S/2 mol HCl = 0.0112 moles

 

mass (in g) of H₂S = 0.0112 mol x 34 g/mol = 0.382 g