J.R. S. answered 05/21/18
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
First alloy: 200 g x 0.45 Cu = 90 g of Cu
Second alloy: 120 g x 0.75 Cu = 90 g Cu
Final mixture = 320 g containing 180 g copper (56% copper)