zinc metal reacts with aqueous hydrochloric acid to produce hydrogen gas and zinc (II) chloride.

Question

Zn(s) + 2HCI(aq)=H₂(g)+ZnCl_2(g)

 

How many mL of 1.67M HCI solution are needed to completely react 11.5g ofZn?

Answer 1

Balanced equation:

Zn(s) + 2HCl(aq) ==> ZnCl₂(aq) + H₂(g)

moles Zn present = 11.5 g x 1 mol/65.4 g = 0.176 moles

moles HCl needed = 0.176 moles Zn x 2 moles HCl/mole Zn = 0.352 moles 

volume (ml) HCl needed: 1.67 mol/L (x L) = 0.352 moles and x = 0.211 L = 211 mls