J.R. S. answered 04/12/18
Tutor
5.0
(145)
Ph.D. in Biochemistry--University Professor--Chemistry Tutor
10.5 g C6H6 x 1 mol/78 g = 0.1346 moles C6H6
0.1346 moles x 3.9099x103 kJ/4 moles = 526 kJ
q = C∆T C = q/∆T = 526 kJ/27.5ºC C = 19.1 kJ/ºC