J.R. S. answered 04/02/18
Tutor
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Ph.D. in Biochemistry--University Professor--Chemistry Tutor
0.01975 L x 0.1 mole/L = 0.001975 moles AgNO3
AgNO3 + Cl- ==> AgCl(s) + NO3-
0.001975 moles AgNO3 = 0.001975 moles of Cl-
mass of Cl- = 0.001975 moles x 35.45 g/mol = 0.0700 g Cl-
0.0700 g/x g = 0.2787
x = 0.2512 grams