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Question

What is the molarity of ZnCl2 that forms when 30.0 g of zinc completely reacts with CuCl2 according to the following reaction? Assume a final volume of 260 mL .
Zn(s)+CuCl2(aq)→ZnCl2(aq)+Cu(s)

Answer 1

A couple of "down" votes for the question indicates that tutors feel you should at least attempt the problem instead of just posting and waiting for an answer. I'll guide you. You do the work.

From the balanced equation, which is given to you, note the mole ratio.  That is 1 mole Zn produces 1 mole ZnCl2.  Find moles Zn in 30.0 g of Zn (hopefully you know how to do this).  Then that will be the same number of moles of ZnCl2 formed (1:1 ratio).  To find the MOLARITY, simply divide that number of moles by the volume in liters (0.260 liters).  Done.