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Question

A 0.72 mg sample of nitrogen reacts with chlorine to form 6.19 mg of the chloride.
What is the empirical formula of the nitrogen chloride?
Express your answer as a chemical formula.

Answer 1

N + Cl ==> NCl

mass of Cl = mass of NCl - mass of N = 6.19 mg -0.72 mg = 5.47 mg Cl

mmoles N = 0.72 mg x 1 mmole/14 mg = 0.0514 mmoles N

mmoles Cl = 5.47 mg x 1 mmole/35.5 mg = 0.154 mmoles Cl

Dividing both by 0.0514 to get 

1 mmole N

3 mmole Cl

Empirical formula is NCl₃