Probability

Question

Let A and B be independent evnets where P(A)=0.3 and P(B)=0.6

Find P(AnB)

Find P(AuB)

Find P(AnB’)

Answer 1

P(AnB) = P(A) * P(B) = 0.18
This means that there is .18 overlap between A and B. Therefore
P(AuB) = P(A) + P(B) - P(AnB) = .3 + .6 - 0.18 = 0.72
P(AnB’) = P(A) * (1-P(B)) = .3 * .4 = .12