The density of gold is 19.32 g/cm3. Calculate the volume of the sample of gold in liters that weighs 2.416 kg?

Question

 The density of gold is 19.32 g/cm3. Calculate the volume of the sample of gold in liters that weighs
2.416 kg?

Answer 1

Convert density to 19.32 kg/L or convert 2.416 kg to 2416 g so that you have consistent units.

Then using dimensional analysis:

 

2.416 kg x 1 L/19.32 kg = 0.1251 Liters

 

2416 g x 1 cm3/19.32 g x 1 L/1000 cm3 = 0.1251 Liters

Answer 2

Density = Mass/Volume

 

Volume = Mass/Density

 

           2.416 km = 2416 grams

 

           2416 grams / 19.32 g/cm^3 = 125.052 cm^3

 

 

1 gallon of gold weighs 160.19 lb, which is 19.3 x 8.3 the density of water.

1 cubic meter weight 42509.5 lb.

http://www.traditionaloven.com/metal/precious-metals/gold/convert-qty_1-cubic-metre-m3-gold-to-pound-lb-of-gold.html

                             1 cubic meter           42509.5 lb         1 gallon             3.78542 liters

125.052 cm^3 * -------------------- * ---------------- * ------------------ * -----------------  = .12561 liters

                                (100 cm)^3        1 cubic meter     160.19 lb            1 gallon