
Jacob C. answered 07/22/21
Adaptive Math and Physics Tutor
A critical value is x = -1 as that will yield 0 in the denominator, causing the left-hand side to be undefined. Another critical value is x = 0 as that will cause the left-hand side to equal 0. We consider values of x such that x < -1, -1 < x < 0, and x > 0.
x < -1:
Choose x = -2 such that 5x/(x + 1) = 5(-2)/(-2 + 1) = 10. The expression will be positive when x < -1, so the interval (-∞, -1) is not part of the solution.
-1 < x < 0:
Choose x = -0.2 such that 5x/(x + 1) = 5(-0.2)/(-0.2 + 1) = -1.25. The expression will be negative when -1 < x < 0, so the interval (-1, 0) is part of the solution.
x > 0:
Choose x = 4 such that 5x/(x + 1) = 5(4)/(4 + 1) = 4. The expression will be positive when x > 0, so the interval (0, ∞) is not part of the solution.
Thus, the interval for which 5x/(x + 1) < 0 is simply (-1, 0).