how many liters of ammonia gas will be produced when 5 moles of ammonium hydroxide decompose

Question

We need to have balanced equation, mole ratio and volume ratio. 

Answer 1

NH4OH(aq) ===> NH3(g) + H2O(l)  balanced equation

 

mole ratio is 1 mole NH4OH produces 1 mole of NH3 (gas)

5 moles NH4OH = 5 moles NH3

The volume occupied by 5 moles NH3 gas will depend on the temperature and pressure. Assuming STP (standard temperature of 0ºC and standard pressure of 1 atm), 5 moles x 22.4 liters/mole = 112 liters of NH3 gas.