Solve the equation.

Question

Solve the equation. 

 

3e^x + 2 = 9         

 

The solution(s) is/are x = ?

Answer 1

Hi Keith,

 

You first want to isolate the term with e, so subtract 2 from both sides of the equation:

 

3e^x = 7

 

Now divide both sides by 3:

 

e^x = 7/3

 

now take the natural log of both sides:

 

ln e^x = ln 7/3

 

Do the power rule of logarithms:

 

x ln e = ln 7/3

 

To isolate x, divide both sides by (ln e):

 

x = (ln 7/3) / (ln e)

 

plug that into your calculator and you should get x is approximately 0.847.