Let L = light color allele
Let l = dark color allele
p2 + 2pq + q2 = 1
light color = dominant (LL) + heterozygous (Ll) = 19 %
dark color = recessive (ll) = 81 %
q2 = 0.81
q = 0.9 = 9/10
p2 + 2p(9/10) + (9/10)2 = 1
(p + 9/10)2 = 1
sqrt(p + 9/10) = sqrt(1)
p + 9/10 = 1
p = 1/10
pq = 1/10 * 9/10 = 9 / 100
ANSWER: 9 %
Tram N.
02/18/18