Verify: cosusinv=1/2[sin(u+v)-sin(u-v)

Question

This is for my trig class, thanks for the help!

Answer 1

1/ 2 ( Sin ( u +v) - Sin ( u - v) ) =

 

1/ 2 [ (Sin U CosV  + Sin V Cos U ) - ( sin u Cos V - CosU Sin V)] =

 

1/ 2 ( 2 Sin V Cos U)=

 

    2 Sin V Cos U