15 Answered Questions for the topic Verify

06/27/19

If Tan^2(t)-Sin^2(t)=Sin^a(t)/Cos^b(t), then the positive power a= ALSO the positive power b=

So, I know the first two stepssin^2(t)/cos^2(t) -sin^2(t)sin^2(t)-sin^2(t)cos^2(t)/(cos^2(t)I have no idea what to do after this? I looked and it said to factor but I have no idea why you factor... more
Verify Identities

01/30/18

Examine the following identity verification: a) identify the error and explain why it is a problem b) correctly verify the identity

tan (θ+ pi/2)= (tan θ + tan pi/2)/(1-tan θ tan pi/2)= (((tanθ)/(tan pi/2))+1)/ ((1/tan pi/2) -tan θ)= (0+1)/ (0-tan θ)= 1/ -tan θ= - cot θ

12/19/17

Verify sin2X=(2tanX)/(1+tan^2X)

I need to verify this for homework and im confused
Verify

07/22/17

(tan\theta -cot\theta )/(tan\theta +cot\theta )+2cos^(2)\theta =1

(tanΘ -cotΘ )/(tanΘ +cotΘ )   +  2cos2Θ =1

03/28/17

Prove that these are identities

2cosx - secx = cosx - tanx/cscx

what is the best option to verify sec(y)cos(y)=1

options   a. cot u =sin (u)/cos(u) b. sec(-u)=sec(u) c. 1+tan^2(u)=sec^2(u) d.cos (u)=1/sec(u)  

05/12/14

tan^2x(csc^2x-1)=1

what are the steps to verify this trig identity
Verify Trigonometry

04/18/14

cot^2x-cos^2x=cot^2x cos^2x

Verify the identity

01/05/14

Use the quadratic formula to find all solutions in the interval [0,2pi): tan^2x-6tanx+4=0

This is for my trig class, thanks for the help!

01/05/14

Verify: sin9x+sin5x/cos9x-cos5x=cot2x

This is for my trig class, thanks for the help!

01/05/14

Verify tan^4x+2tan^2x+1=sec^4x

This is for my trig class, thanks for the help!

01/05/14

Verify: 1+cosx/sinx+sinx/1+cosx=2cscx

This is for my trig class, thanks for the help!

01/05/14

Verify: cosusinv=1/2[sin(u+v)-sin(u-v)

This is for my trig class, thanks for the help!

01/05/14

Verify tan(x+pi/4)= 1+tanx/1-tanx

This is for my trig class, thanks for the help!
Verify

02/21/13

2-tan^2 x=3-sec^2 x

I need to verify this question to make the identities match

Still looking for help? Get the right answer, fast.

Ask a question for free

Get a free answer to a quick problem.
Most questions answered within 4 hours.

OR

Find an Online Tutor Now

Choose an expert and meet online. No packages or subscriptions, pay only for the time you need.