find two consecutive integers whose product is 24 more than three times the first integer

Question

I just want to know how to solve it 

Answer 1

find two consecutive integers whose product is 24 more than three times the first integer

 

Hi Veronica, 

Step One: Create Let Statements

Let x=the first consecutive integer

Let x+1=the next consecutive integer

Step Two: Create an equation

24+3x=x(x+1) Distribute

24+3x=x²+x Rearrange

0=x²+x-3x-24 Combine Like Terms

0=x² -2x-24

0=(x+4)(x-6)

We take the positive value: x=6

∴The integers are 6 and 7. 

Best, 

Starlyte H.

Answer 2

Veronica,

 

x = first integer

x + 1 = 2nd integer

 

writing the problem as an algebraic equation.

x(x+1) = 3x+24

 

From here you can solve for x.