If the initial temperature of an ideal gas at 2.250 atm is 62.00 °C, what final temperature would cause the pressure to be reduced to 1.650 atm?

Question

Help would be greatly appreciated! 

Answer 1

Using Gay-Lussac's Law, we have P₁/T₁ = P₂/T₂

We have P₁ = 2.25 atm

T₁ = 62 C = 335 K

P₂ = 1.65 atm

 

So T₂ = P₂ /(P₁/T₁)  = (1.65 / (2.25/335))=245.7 K = -27.3 C