A). {(2x2y3) ÷ (3xy4)}2 = {(2/3)xy-1}2 = (4/9)x2y-2
= 4x2/(9y2)
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B). {(x3y-2) ÷ (x-1y5)}-1 = {x4y-7}-1
= x-4y7 = y7/x4