
Jack C. answered 10/15/15
Tutor
4.5
(28)
Former Cal Sate Dominguez Hills Teacher for over fifteen years
It does not look reasonable as a constant proportion situation. In a vacuum any object will fall at 32Ft/second squared.
Theoretical with no air drag
So .8 seconds = 32ft * .8^2seconds= 32ft * .64seconds =20ft
In 1.5 seconds =32* (1.5)^2= 32/ft/ second *.25seconds= 72
In 3.1 seconds = 32 * (3.1)^2= 32ft/ second * 9.61 seconds= 307.52 Ft.
Observed Theoretical
Time Distance Rate Time Distance Rate
.8 100 125 ft/s .8 20 25 ft/S
1.5 187.5 125 ft/s 1.5 72 48 ft/S
3.1 500 161. Ft/S 3.1 307 99 ft/s
The observed seems to indicate that the object is picking up additional speed as time goes on. This would indicate acceleration due to time. This is not a direct proportion problem.
Theoretical with no air drag
So .8 seconds = 32ft * .8^2seconds= 32ft * .64seconds =20ft
In 1.5 seconds =32* (1.5)^2= 32/ft/ second *.25seconds= 72
In 3.1 seconds = 32 * (3.1)^2= 32ft/ second * 9.61 seconds= 307.52 Ft.
Observed Theoretical
Time Distance Rate Time Distance Rate
.8 100 125 ft/s .8 20 25 ft/S
1.5 187.5 125 ft/s 1.5 72 48 ft/S
3.1 500 161. Ft/S 3.1 307 99 ft/s
The observed seems to indicate that the object is picking up additional speed as time goes on. This would indicate acceleration due to time. This is not a direct proportion problem.
The sky diver is moving faster that expected and we have not accounted for air drag.