
George M. answered 04/02/16
Tutor
5
(4)
Tutor in Physics, Science, Math. (MS Physics, UT Dallas)
Hi Sofia!
I am going to leave part of the problem for you to work.
Step 1: We break each vector into its x and y components using the trigonometry of sines and cosines. Make sure to pay attention to the positive and negative signs when doing this.
F1x=F1[cos(281)]=81N( )
F2x=F2[cos(228)]=52N( )
F1y=F2[sin(281)]=81N( )
F2y=F2[sin(228)]=52N( )
Step 2: We add the x-components to get the x component of the resultant vector.
Rx=F1x+F2x=
Step 3: We add the y-components to get the y component of the resultant vector.
Ry=F1y+F2y=
Step 4: We use the Pythagorean Theorem to compute the magnitude of the resultant from the x and y components of the resultant.
R=SQR [Rx2+Ry2]
Step 5: We find the angle that R makes with the nearest x-axis from tan(theta)=(Ry/Rx), so theta=arctan(Ry/Rx)