Meena S. answered 06/15/15
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Hi Nima,
Suppose x1, x2, x3, ........xn are n observations.
Sum Of Squares = x12 +x22 +............+xn2.
Let Degree of Freedom = df
Mean Squares = Sum Of Squares / df
eg A) Sum Of Squares = 19.29
Degree of Freedom = 2
Mean Squares = 19.29/ 2 = 9.64
F = 331.83
p <0.0001 which is < 0.05 so ANOVA Test is Significant, Reject Null Hypothesis.
Similarly you can do remaining.
FYI: Types of ANOVA like ...One -Way ANOVA, Two-WAy ANOVA....
Nima P.
06/15/15