graph y=3x+1 pls

Answer 1

y = 3x + 1

is a linear equation, a straight line ("line-ar means "line")

It's in slope intercept form, where the constant term = the y intercept 1 = the point (0,1)

coefficient of the x term = the slope = 3

easiest way to graph it is find a 2nd point such as (x,y) = (3, 10) Then plot (3,10) and (0,1), and connect them with a straight line.

then put arrows at the ends of the line to indicate the line goes forever in both directions

Answer 2

Answer 3

This is the equation for a straight line (y = mx + b). All you need is two points (plus perhaps a third point as a check).

Pick 2 - 3 values for x and calculate the resulting y. This will provide enough ordered pairs on the xy plane to connect them with a ruler.

Ex: x = 0, y = 3(0) + 1 = 1 Plot point (0,1)

x = 2, y = 3(2) + 1 = 7. Point is (2,7)

x = -2, y = 3(-2) + 1 = -5. Point is (-2,-5)

Answer 4

Hi Maya,

The first thing I would do is identify the function's behavior. Since this is a linear function it will follow y=mx+b. Hence, for the given equation y=3x+1 has the y-intercept 1 and increases by 3 units on the y-axis for every increase in one unit on the x-axis. We can then plug in values to find points on the graph which we can connect so when x=0, y=1 and when x=1, y=4.

I would recommend using Desmos as a tool to understand function behavior!

Answer 5

The way that you can graph this easily is by identifying the y-intercept and the slope in your line equation.

First, draw the x and y coordinate plane.

In the equation y = 3x + 1, the y-intercept is positive 1, so draw a point at (0, 1). Then, you know that the slope is a positive 3 (the coefficient next to the x term). From (0, 1) move up 3 and to the right by 1. Draw another point at (3, 2). Connect these points with a ruler/protractor, and you now have the line!

Hope this was helpful.