Hi, to answer this question, let us break it down into pieces. We are trying to find the slope and the y-intercept of the equation y=(2/3) x + 6.
The first step is to rearrange the equation into slope-intercept form. We are in luck, and because the equation is already in slope-interest form.
Slope-intercept form is represented in generic terms as y=mx+b, where m is your slope and b is your y-intercept.
To define the slope of a line, and the we are looking at the steepness of the line. It's like how much the line goes up or down as you move front left to right on an xy graph. If it goes up, it is a positive slope. On the other hand, if it goes down it is a negative slope. The steeper the line the bigger the slope.
Also when we refer to an equation of a line in slope-intercept form, which is we are always referring to the y-intercept. The y-intercept is the value of y where the line crosses when x=0.
In our case, the it is already in the correct forn so we just have to plug in the right values.
The slope "m" = - 2/3
The y-intercept "b" = 6