VERY CONFUSED-Hardy Weinberg blood type problem

Question

The I^A "allele" for the ABO blood groups actually consists of two subtypes, I^A1 and I^A2, either being considered "I^A". In Caucasians, about 3/4 of the I^A alleles are I^A1 and 1/6 are I^A2 (Cavalli-Sforza and Edwards, 1967).

What would be the expected proportions of.......

I^A1 I^A1

I^A1 I^A2

I^A2 I^A2

........among I^A I^A individuals?

Answer 1

See the video for a walkthrough of the problem. I started by correcting an error in the question, then used a visualization of HW calculated the expected genotype frequencies.

Answer 2

Just multiply the proportions of each allele. So for I^A1 I^A1 individuals it would be 3/4 x 3/4. Do the same for the other two.