
Yefim S. answered 03/11/24
Math Tutor with Experience
f(x_ = ln(√I(1 - x2))
a)1 - x2 ≠ 0; x ≠ ±1
Domain: (- ∞, - 1)U(-1 , 1)u(1, ∞)
b) If - 1 < x < 1, then lf(x) = ln(√I1 - x2I)) = 1/2ln(1 - x2); f'(x) = 1/2·1/(1 - x2)·(- 2x) = x/(x2 - 1)
If x from (- ∞, - 1)U(1, ∞) then f(x) = 1/2ln(x2 - 1); f'(x) = 1/2·1/(x2 - 1)·2x = x//(x2 - 1)
Answer: f'(x) = x/(x2 - 1)