Josh D.
asked • 02/27/24help out :) calculus
Use the implicit differentiation method to find the equation of the line that is tangent to the curve e ^ (- (x ^ 2 + y)) = x + y + 1 at the point P(1, 1).
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1 Expert Answer
LEV K. answered • 02/28/24
Tutor
New to Wyzant
The curve doesn't pass through point (1,1). Plug-in 1 for X and 1 for Y. You will get e^(-2) = 3 which is false
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William W.
(1, 1) is not a point on e^(-(x^2 + y)) = x + y + 102/27/24