The rate of cooling is in proportion to the difference in T between the bowls and the environment. This means cooling is faster in the freezer.
Sorry, misread the problem
Newton's Law of Cooling: dT/dT = -U(T-Tf)
General solution for 0 to 1 min.
T=(Tb - TF)e^(-Ut) + TF. (F= freezer)
For 1 minute
T(1) =(Tb - TF)e^(-U) + TF
Substitute f to indicate refrigerator.
For second minute we can build the solution for 1 minute from new initial temperatures
Let's look at the one that went from Freezer to fridge
At 2 min setting t=1 as 0
((Tb-TF)e^(-U)-TF-Tf)e^(-U) + Tf and the same with F and f switched for the other bowl
If you equate the temperatures, I get that they are equal if e^(-2U) =1. If >1 the freezer first dominates as it is clear when U is high enough that T after 1 min can be less than T fridge and T warms up in the second minute but has to end less than Tf.
Interesting problem. Not sure I got through it unscathed.
Anthony T.
The problem says the bowls are switched between freezer and fridge after one minute.02/15/24