A) 2x + 4y = 3: What is the value of x when y is zero? 2x + 4(0) = 3. This value will be the x intercept. It won't be on the line above the x.axis where values of y are positive, won't be on the line below the x.axis where y is negative, but it will be on the line where the line has a value of zero for y, i.e. it will also be on the x.axis. Solve 2x = 3 for x and this will be the value of x when y is zero.
Similarly, what is the value of y on this line when x is zero? 2(0) + 4 y = 3. Solve 4y = 3 for y to get the y.intercept.
B) y = √2 x - 2/3: Here the y intercept is easy because it is in slope-intercept form of y = mx + b. b is the y.intercept. Careful. Is b = +2/3 or -2/3.
Now the x intercept is more difficult. Solving for x yields x = (y + 2/3)/√¯2 and when y = 0, x is (√¯2) / 3.
c) x = -2: sketch the x-y coordinate plane. Lay your pencil vertically along the y.axis. While maintaining the attitude of your pencil, displace it 2 units to the left of the y.axis. What axis is intercepted - the x or the y? What is the x intercept. Does it intercept the y axis?
y is not defined here. There is nothing to tell you what y is. y is from -∞ to ∞. So y can be a lot of things.
y can even be equal to y = (x/0.00000000000000000000000000000000000000000000001) - 2, but...
but y CAN NOT be y = x/0 -2. Thou shalt not divide by zero.
d) y = 0: mark all the points on the x-y cartesian coordinate plane where y = 0. Ok, you can stop....Hey! Stop! Oops.... Well, if you ever stop, and read this, what did all of those points form?
e) x = 2y: It won't hurt to solve for y, or simply divide by 2 on both sides:
y = x/2 or y = (1/2 ) x, or y = (1/2) x + 0.
So now it is in slope intercept form and the y.intercept is 0 and back to x = 2y, x = 0 when y is 0, so the x.intercept is 0.