your expression is 6x2+49x-45
FIRST look for greatest common factors. Do you see any (1 is not useful as a factor)? I don't.
SECOND look for special, recognizable cases, to save time. These are like a2+2ab+b2 or a2-b2, etc. I don't see any of these either.
Next, I like a method I call the product-sum method. I find factors of a*c that sum to to b.
Since our expression is in standard form, a=6, b=49, and c=-45.
I want factors of a*c=(6)*(-45)=-270
FACTORS OF -270:
2 -135
3 -90
5 -54
6 -45
9 -30
10 -27
15 -18
18 -15
27 -10
30 -9
45 -6
54 -5
90 -3
135 -2
Those are all the factor pairs I can find. Once you get used to this method you won't actually have to list them all. Do you see a pair that sums to b? Remember, b=49
I see that (54)+(-5)=49, so let's use that. We're going to split our middle term b into those two terms, which doesn't change anything but allows us to factor by grouping.
6x2+49x-45
6x2+54x-5x-45
Take a close look at how I split that middle term, how I didn't really change the value of the expression, and where I got those numbers.
Now, factor by grouping.
(6x2+54x)+(-5x-45)
What is the largest thing I can factor out of the first two terms? the last two terms?
6x(x+9)-5(x+9)
Now I can factor out the binomial (x+9) from both terms
(6x-5)(x+9)
Double check that this is the correct factorization by distributing these two binomials.
Patrick W.
03/30/15