Danielle Z.

asked • 03/30/15

how do you factor 6x^2+49x-45

they all have a common factor of 1 but you wouldn't need to do that here so cant you just go ahead and factor the equation out?

3 Answers By Expert Tutors

By:

Olubunmi B. answered • 03/30/15

Tutor
4.9 (32)

Math Professional

Patrick W.

Don't forget to divide by 2a
 
I think that turns your answers into 10/12 and -108/12
 
However, the difference between finding the zeros of an equation and finding the factored form of an expression is not trivial and I think it is worth seeing it both ways. Using your answers, we might accidentally write this expression in factored form:
(x-10/12)(x+108/12)
which has the correct zeros, but is missing a factor of 6 from the original expression:
6(x-10/12)(x+108/12)
 
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03/30/15

Olubunmi B.

Danielle, I assumed you knew this but in case
 
since x=-9 and x=5/6
its factors will be written as (x+9)(6x-5)...note it's the  negative in the factor. Since 6 was the denominator, we know it carried the x variable.
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03/30/15

Patrick W. answered • 03/30/15

Tutor
4.9 (28)

High School Mathematics Teacher, Passionate Math Geek

Danielle Z.

they didn't have any common factors either for you to break down the problem more. I guess thats what i was wondering you do have to do quite the factoring and moving of signs and numbers to figure it out exactly.
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03/30/15

Arthur D.

tutor
look at the problem like so:
6x2+49x-45
6*45=270
270=2*3*3*3*5
combine the products so that their difference is 49
this is basically what Patrick did only he listed all the products and like he said when you get the hang of it you won't have to list all products
270=2*3*3*3*5=(2*3*3*3)*(5) and 54-5=49, the coefficient of the middle term
now it's a little simpler from here...
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03/30/15

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