Heat Transfer│Please Help!

Question

49 g of an unknown metal is heated to a temperature of 150.0 C. A calorimeter is filled with 120.0 g of water at an initial temperature of 20.0 C. The specific heat capacity of water is 4.184 J/gC.

The hot metal is placed inside the calorimeter and the system is allowed to reach equilibrium. The equilibrium temperature is 22.70 C.

How much heat did the water absorbed from the metal?

Answer 1

Once the metal is placed in the calorimeter, there will be a transfer of heat from the metal to the water, as both equilibrate to the same final temperature 22.7C.

As for the water, the absorbed heat reads: Q = m c_{H20} (T_f - T_i), where T_i = 20C (initial temperature)

T_f = 22.7C (final temperature)

m = mass of water = 120g

c_{H20} = 4.184 J/gC (specific heat)

Plugging in the numbers gives the numerical result