what is the right x value?

Question

"Calculator to figure out the x value of an image box based on direction, display width, and the amount of pixels that you don't use (the empty spaces on either side of the screen combined). a_unused is the amount of pixels that you didn't use on both sides combined. d_width is the amount of pixels in the width of the screen. d_direction is the direction, where -100 = 100% Left and +100 = 100% Right."

Formulas: a_used = d_width – a_unused

x = (a_used/2) + (a_used * ((d_direction/100) / 2)) + (a_unused/2)

Question: Why does this formula not work? (For example, if I enter a direction that is negative and should show on the left side, it shows on the right side.)

Answer 1

If you're getting the image on the opposite side of the expected direction, it could be due to the sign of d_direction. Make sure that you're using negative values for left and positive values for right. For example:

1. If you want the image to move 100% to the left, d_direction should be -100.
2. If you want the image to move 100% to the right, d_direction should be 100.

Double-check your input values for d_direction to ensure that they align with your desired direction.