A design consists of three squares placed side by side. The area of each square is 50 square centimeters. To the nearest tenth of a centimeter, what is the perimeter of the design?

Answer 1

From the given conditions and the fact that A = s² is the area of a square with a side of length s, we can deduce that s = √(50 cm²) = (√50) cm. We can also deduce from the given conditions that the long sides of the design each have a length of 3s = (3√50) cm and the short sides of the design each have a length of s = (√50) cm. Since the design has two long sides and two short sides, we can conclude that the perimeter of the design is P = 2((√50) cm) + 2((3√50) cm) = (2√50) cm + (6√50) cm = (8√50) cm = 56.6 cm.

Answer 2

See attached video for and explanation and steps in solving for the perimeter.