Inactive Tutor answered 06/14/23
total cost of a call = 10x +49 per month, where x is the minutes of long distance calls made.
10x+49 <= 80, 10x <= 31, x <=3.1 minutes of long distance calls
Peter R.
06/14/23
Katherine B.
asked 06/14/23I’m having trouble with this problem.
My cell phone company charges $49 per month plus $.10 per minute for long distance calls. Write an equation that represents the total cost C for x minutes of long distance calls. How many minutes of long distance calls can I make and stay within my limit of $80?
Inactive Tutor answered 06/14/23
total cost of a call = 10x +49 per month, where x is the minutes of long distance calls made.
10x+49 <= 80, 10x <= 31, x <=3.1 minutes of long distance calls
Peter R.
06/14/23
Hello, thank you for taking the time to post your question!
Based on the information given in the question the underlying formula here would be
C = 0.10x + 49
Solving then for C = 80 gives
80 = 0.10x + 49
31 = 0.10x
x = 310
that means that you can make 310 minutes of long-distance calls and stay within the $80 limit.
I hope that helps get you moving in the right direction! Feel free to reach out if you have any additional questions beyond that :)
Inactive Tutor answered 06/15/23
Total cost (C) >= $49/month + $.10(x), where x is the number of long distance calls made.
C >= 49 + .1x if the total cost is limited or equal $80 then,
80>= 49 + .1x
Solve for x by subtracting 49 from both sides
31>= .1x
Divide both sides by .1
31/.1 >= x
310 minutes >=x
We can't exceed 310 minutes of long distance calls
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Katherine B.
Thank you so much!06/14/23