Conservation Question (Look at description for more details; PHYSICS Related)

Question

How much heat (in Joules) is required to melt 0.31 kg of ice at 0^oC and to raise the temperature of the melted ice to 15^oC? The specific heat of water is 4186 J/(kg K) and the Latent heat of fusion of water is 334,000 J/kg.

Answer 1

The energy required to melt the water is (334,000 J/kg)(0.31 kg) = 103540 joules

The energy required to heat the melted water to 15°C is:

Q = mC_pΔT

Q = (0.31 kg)(4186 J/(kg K))(15 - 0) [notice I used °C. The correct way would be to use Kelvin however since it is the difference we are seeking, the numerical result is the same)

Q = 19464.9 joules

Q_TOTAL = 103540 joules + 19464.9 joules = 123000 joules