
Shelli O. answered 03/22/23
MIT Undergraduate, UCLA Ph.D. Specializing in Math
A parabolic function is of the form:
y = ax2 + bx + c
in this case it is more convenient to write
s = an2 + bn + c
s(1) = 2an + b
s is in thousands of units. Therefore
s(1) = a(1)2 + b(1) + c = 7
s(2) = b(2)2 + b(2) + c = 17
We also know s(2) is where the function peaked, which means s(1)(2) = 0 or the first derivative of the function is 0 when n = 2
s(1) (2) = 2a(2) + b = 4a + b = 0
You now have 3 equations with 3 variables and you can do the algebra to solve for a, b, and c