100mL of a solution that is simultaneously 15.6 mg/mL malonic acid, 3.38 mg/mL MnSO4 • H2O, and 0.03% starch

Question

Calculate the g and mL necessary to make this solution

Answer 1

For the malonic acid: 15.6 mg / ml x 100 ml = 1560 mg = 1.56 g malonic acid needed

For MnSO4*H2O: 3.38 mg / ml x 100 ml = 338 mg = 0.338 g of MnSO4*H2O needed

For starch: 0.03% w/v = 0.03 g / 100 ml = 0.03 g of starch needed

Volume of water needed = whatever it takes to make the final volume 100 mls (can't be determined from the info provided).