
Dayv O. answered 02/24/23
Caring Super Enthusiastic Knowledgeable Pre-Calculus Tutor
Isn't it just two criteria - 1.ability to sum and the result be in
the set, and 2. ability to multiply by constant and result be
in the set.
since the constant can be negative the result
would not be in set (now x component<0),
the set is not a vector space.